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akposevictor

Solving the algebraic equations given, the missing numbers in the boxes can be known as shown in the steps below.

Given the equation, ⅔(x - 1) = ⅕(2x - 3) + 1

First, apply the distribution property to open the bracket.

Thus:

⅔x - ⅔ = ⅖x - ⅗ + 1

⅔x - ⅔ = ⅖x + ⅖

  • Subtract ⅖x from both sides

⅔x - ⅖x - ⅔ = ⅖

4/15x - ⅔ = ⅖

  • Add ⅔ to both sides

4/15x = ⅖ + ⅔

4/15x = 16/15

  • Multiply both sides by 15/4

x = 16/15 × 15/4

x = 4

Given the equation, 3c - 3 + 2(3c + 1) = - (3c + 1)

  • Open the bracket using distributive property

3c - 3 + 6c + 2 = -3c - 1

  • Add like terms

9c - 1 = -3c - 1

  • Add 3c to both sides

9c + 3c - 1 = -1

12c - 1 = -1

  • Add 1 to both sides

12c = -1 + 1

12c = 0

  • Divide both sides by 12

c = 0

Learn more about algebraic equations on:

https://brainly.com/question/7784687

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