is (x-3) a factor of 2x^3 - 4x^2 - 6?
what is the remainder?
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Answer:
Not a factor; r = 12
Step-by-step explanation:
By dividing this binomial factor of x-3 by the polynomial we can determine whether it is a factor. If the answer has no remainder, we know that it is a factor.
[tex]\frac{x-3}{2x^3-4x^2-6}[/tex]
Lol pretend that is switched, I messed up.
I used long division to determine the answer. When you do it, don't forget to add a '0x' in between the 2nd and 3rd terms, so that it lines up correctly.
The answer i got was 2x^2 + 2x + 6 with a remainder of 12. This means that x-3 is not a factor and the remainder is 12.
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