Given MN shown below with M (-6,1) and N (3,-5) find the equation of the line that runs through P and is parallel to Mn. please show all work.
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Answer:
y = [tex]-\frac{2}{3}x[/tex] + 5
Step-by-step explanation:
Find the slope of MN, which is [tex]\frac{1-(-5)}{-6-3} = \frac{6}{-9} = -\frac{2}{3}[/tex]
Then, use the formula: y-y₁ = m(x-x₁)
Use point P as (x₁, y₁)
Plugging in x₁ = 6 and y₁ = 1 and simplifying, we find that:
y - 1 = [tex]-\frac{2}{3}[/tex] (x - 6)
Simplify to find that:
y = [tex]-\frac{2}{3}x[/tex] + 4 + 1
y = [tex]-\frac{2}{3}x[/tex] + 5