Answer: [tex]\large \boldsymbol {\sf 22\dfrac{2}{3} }[/tex]
Step-by-step explanation:
[tex]\displaystyle \large \boldsymbol {} \sf Find \ \ 4 a \ \ ; \ \ if \ a=5\frac{2}{3} \\\\1-st \ method \\\\ 5\frac{2}{3} =5+\frac{2}{3} \ \ then \\\\ 4\cdot \bigg(5+\frac{2}{3} \bigg)=4\cdot 5+ \frac{4\cdot 2}{3} =20+\frac{8}{3} =20+2\frac{2}{3} =\boldsymbol {\sf 22 \frac{2}{3} } \\\\\\ 2-nd \ \ method \\\\ 5\frac{2}{3} =\frac{5\cdot 3+2}{3} =\frac{17}{3} \\\\\\ 4\cdot \bigg( \frac{17}{3} \bigg) =\frac{4\cdot 17}{3} =\frac{68}{3} =\boldsymbol {\sf 22 \frac{2}{3}}[/tex]
