a polynomial has been factored below but some constants are missing. 2x^3-8x^2-24x=ax(x+b)(x+c)
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Answer:
The polynomial is 2x^3 - 8x^2 - 24x
And we can factor out a 2x from each of the three terms:
2x(x^2 - 4x - 12)
Lastly, factor the remaining quadratic:
2x(x+(-2))(x+6)
And we have our answer:
a=2
b=-2
c=6
Let me know if this helps!
Answer:
a =2, b =2, and c = -6
Step-by-step explanation:
We factor the polynomial and then see which value corresponds to what.
2x^3-8x^2-24x
As we see it, all terms are factorable by 2x. So if we take out 2x from every term, we get
2x(x^2 - 4x - 12)
Now we factor the quadratic, which we can do mentally to get
2x(x+2)(x-6)
ax(x+b)(x+c)
Comparing that to ax(x+b)(x+c), we can tell that a =2, b =2, and c = -6.