I would appreciate it so much if anyone helps me on these answers please!
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Answer:
see explanation
Step-by-step explanation:
(14)
tan F = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{GH}{FH}[/tex] = [tex]\frac{12}{5}[/tex]
(15)
sin G = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{FH}{FG}[/tex] = [tex]\frac{5}{13}[/tex]