In a certain Algebra 2 class of 28 students, 9 of them play basketball and 17 of them play baseball. There are 6 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?
What is the probability that a student chosen randomly from the class plays both basketball and baseball?
Answer:
Because we know there are 28 total students in the class and 6 play neither basketball nor baseball, then there are 28-6 = 22 students who either play ONLY basketball, ONLY baseball, or both
We know that 9 out of the 22 play basketball and 17 out of the 22 play baseball
Therefore, 22-9 = 13 students play ONLY basketball, and 22-17 = 5 students play ONLY baseball
This means that the amount of students that play BOTH basketball and baseball is 22-(13+5) = 22-18 = 4 students
Therefore, the probability that a student chosen randomly from the class plays both basketball and baseball is 4/28 or 1/7