The equation of the line that passes through the point (1, 2) and is parallel to the line 3x + 4y = 12.
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Answer:
Step-by-step explanation:
We first turn 3x+4y=12 into standard form:
4y=-3x+12
y=-3/4x+3
By knowing the 2nd line is parallel to the first, the slopes are the same:
y=-3/4x+b
Plugging in (5,4) into the equation:
4=-15/4+b
b=1/4
Final equation=y=-3/4+1/4.