find the length, width, area, and perimeter of a rectangle where the length is 5 units more than the width and the perimeter is 9 times the width
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Step-by-step explanation:
L= W+5
P= 9W
P= 2L+ 2W
9W= 2(W+5) + 2W
9W= 2W +10 +2W
9W = 4W +10
5W = 10
W = 2
L=7
P= 9(2)
P= 18
A= LW
A= 7 x 2
A= 14