Respuesta :
Answer:
31.282 psia
Explanation:
Calculate the mean effective pressure of an ideal Otto cycle
Given data:
compression ratio = 9
inlet pressure ( P1 ) = 14 psia
Initial temperature ( T1 ) = 60°F = 520 R
Final/maximum temp ( T3 ) = 1500°F = 1960 R
using the constant specific heats at room temperature
attached below is the detailed solution
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The mean effective pressure of the ideal Otto Cycle that uses air as the working fluid is; 31.28 psia
We are given;
Initial pressure; P₁ = 14 psia
Initial temperature; T₁ = 60°F = 520 R
Maximum temperature; T₃ = 1500°F = 1960 R
Compression ratio = 9
From tables, the specific heat capacities and constants are;
c_v = 0.171 btu/lbm.R
c_p = 0.24 btu/lbm.R
R = 0.3704 btu/lbm.R
ratio of specific heats; k = 1.4
Let us first calculate the initial volume from the formula;
V₁ = RT₁/P₁
V₁ = (0.3704 * 520)/14
V₁ = 13.7577 ft³/lb.m
- Compression ratio is; V₁/V₂ = 9
Thus;
V₂ = V₁/9
V₂ = 13.7577/9
V₂ = 1.5286 ft³/lb.m
- To get the temperature T₂, we will use the formula;
T₂ = T₁(V₁/V₂)^(k - 1)
T₂ = 520(9)^(1.4 - 1)
T₂ = 1252.277 R
Similarly;
T₄ = T₃/9
T₄ = 1960/(9^(1.4 - 1))
T₄ = 813.87 R
- Formula for heat entering and heat exiting are;
Q_in = c_v(T₃ - T₂)
Q_in = 0.171(1960 - 1252.277)
Q_in = 121.02 btu/lbm
Q_out = c_v(T₄ - T₁)
Q_out = 0.171(813.87 - 520)
Q_out = 50.251 btu/lbm
- Net work done is given by;
W_net = Q_in - Q_out
W_net = 121.02 - 50.251
W_net = 70.769 btu/lbm
Formula for the mean effective pressure is;
mean effective pressure = W_net/(V₁ - V₂)
mean effective pressure = 70.769/(13.7577 - 1.5286)
mean effective pressure = 5.7869 btu.ft³
Converting to psia gives;
Mean effective pressure = 31.28 psia
Read more about compression ratio at; https://brainly.com/question/16014998