Answer:
CI (95%)lb = 576,51
Step-by-step explanation:
Sample Information:
sample size  n  = 12
sample mean  x  =  614 h
sample standard deviation  s  = 59 h
Population with normal distribution, sample size n < 30  in  order to find out CI 95%  significance level is  α = 5 %  α = 0,05  α/2 = 0,025
t(c) for  α/2 = 0,025 and degree of freedom  df =  n - 1  df =  12 - 1 Â
df = 11 Â is:
t(c) = 2,201
CI  =  x  ± t(c) * s / √n
CI (95%) =  614  ±  2,201 * 59 / √12
CI (95%)lb = 614 Â - 37,49
CI (95%)lb = 576,51