I would like help on this math problem please!
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Answer:
4^11
Step-by-step explanation:
[(4^3)(4^4)]÷(4^1+4^-4)
using laws of indices
(4^3)(4^4)=4^(3+4)
=4^7
(4^1 +4^-4)=4^(1-4)
=4^-3
4^7/4^-3,recalling about laws of indices if the exponentials are dividiy ,you subtract the powers give their base is equal
4^7/4^-3=4^(7-(-3)
=4^(7+3)
=4^11