Given:
In right triangle [tex]GHI,m\angle I=90^\circ,GH=7.5,HI=7.2,GI=2.1[/tex].
To find:
The ratio (fraction) for Tan H.
Solution:
In a right triangle,
[tex]Tan\theta=\dfrac{Perpendicular}{Base}[/tex]
In [tex]\Delta GHI[/tex].
[tex]Tan H=\dfrac{GI}{HI}[/tex]
[tex]Tan H=\dfrac{2.1}{7.2}[/tex]
It can be written as
[tex]Tan H=\dfrac{21}{72}[/tex]
[tex]Tan H=\dfrac{7}{24}[/tex]
Therefore, the fraction for Tan H is [tex]\dfrac{2.1}{7.2}[/tex] or it can be written as [tex]\dfrac{7}{24}[/tex].
