What is the vertex for the following quadratic?
f(x)= 2x^2-12x+16
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Answer:
(3, -2)
Step-by-step explanation:
To find the vertex, put the equation into vertex form by completing the square
2(x^2 - 6x) + 16 [pulling out the 2]
2(x^2 - 6x + 9) - 18 + 16 [completing the square, you subtracted 2*9 = 18 so you also add 18]
2(x - 3)^2 - 2 [simplify the equation]
vertex is (3, -2)