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Pythagorean Theorem:[tex]a^{2}[/tex] +[tex]b^{2}[/tex] =[tex]c^{2}[/tex] Question 8 options:

[tex]\sqrt{26} \\\\\sqrt{89}[/tex]

8
5

Pythagorean Theoremtexa2tex texb2tex texc2tex Question 8 options texsqrt26 sqrt89tex 8 5 class=

Respuesta :

kyleighhope

distance formula:

[tex]\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}[/tex]

points:

(-4, -1) and (4,3)

[tex]\sqrt{(-4-4)^{2}+(-1-3)^{2}}[/tex]

[tex]\sqrt{(-8)^{2}+(-4)^{2}}[/tex]

[tex]\sqrt{64+16}[/tex]

= [tex]\sqrt{32}[/tex]
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