ivannatb1708 ivannatb1708
  • 02-03-2021
  • Mathematics
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Help me pleasee I need to turn it in tonightt

Help me pleasee I need to turn it in tonightt class=

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faisal4craft7 faisal4craft7
  • 02-03-2021
Student 1 and student 3 are equivalent
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AnimalPost
AnimalPost AnimalPost
  • 02-03-2021

Answer:

A. Students 1 and 3

Step-by-step explanation:

Student 3's equation is -5r + 3s - 1

Student 1's equation is -(5r - 3s + 1)

We distribute the negative like this: -5r + 3s - 1, which is the same as student 1.

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