Answer:
0.048J/g°C
Explanation:
Given parameters:
Mass of Mercury = 25g
Initial temperature = 25°C
Final temperature = 155°C
Amount of heat absorbed = 455J
Unknown:
Specific heat capacity of mercury = ?
Solution:
To solve this problem, we use the expression below:
Q = m x C x Δt
Q is the heat absorbed
m is the mass
C is the unknown specific heat capacity
Δt is the change in temperature;
455 = 25 x C x (155 - 25)
455 = 25 x C x 130
C = 0.048J/g°C
