Anyone know this?? Question: find the area of the shape. Don’t forget your units and use 3.14 if you need to use pi.
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Area of this shape = 614²
Length of side of the first square = 10
It's area :
[tex] =\tt side \times side[/tex]
[tex] = \tt10 \times 10[/tex]
[tex] = \tt {100}^{2} [/tex]
Thus, the area of the first square = 100²
Length of the side of the second square = 10
It's area :
[tex] = \tt \: side\times side[/tex]
[tex] =\tt 10 \times 10[/tex]
[tex] = \tt{100}^{2} [/tex]
Thus, the area of the second square = 100²
Length of the side of the third square = 10
It's area :
[tex] =\tt side \times side[/tex]
[tex] = \tt 10 \times 10[/tex]
[tex] = \tt {100}^{2} [/tex]
Thus, the area of the third square = 100²
(pi value = 3.14)
Radius of the first semicircle = 10 cm
It's area :
[tex] = \tt \: \frac{\pi {r}^{2} }{2} [/tex]
[tex] = \tt \frac{3.14 \times 10 \times 10}{2} [/tex]
[tex] = \tt\frac{3.14 \times 100}{2} [/tex]
[tex] =\tt \frac{314}{2} [/tex]
[tex] =\tt {157}^{2} [/tex]
Thus, the area of the first semicircle = 157²
Area of the second semi circle :
= area of the first semicircle
= 157²
Thus, the area of the second semicircle = 157²
Total area of the figure :
= Area of the 3 squares + Area of the two semi circles
[tex] =\tt 100 + 100 + 100 + 157 + 157[/tex]
[tex] = \tt300 + 314[/tex]
[tex] = \tt {614}^{2} [/tex]
Therefore, the total area of the figure = 614²