When a golf club hits a 0.0459 kg ball at rest, it exerts a 2380 N force for 0.00100 s. What is the speed of the ball afterwards? (Unit = m/s)

Answer:
51.85m/s
Explanation:
Given parameters:
Mass of ball = 0.0459kg
Force = 2380N
Time taken = 0.001s
Unknown:
Speed of the ball afterwards = ?
Solution:
To solve this problem, we use Newton's second law of motion:
F = m x [tex]\frac{v - u}{t}[/tex]
F is the force
m is the mass
v is the final velocity
u is the initial velocity
t is the time taken
2380 = 0.0459 x [tex]\frac{v- 0}{0.001}[/tex]
0.0459v = 2.38
v = 51.85m/s
Answer:
2.38
Explanation:
F = dp/dt --> dp = F*dt ---> p = F*t if F is constant over time so
p = 2380N* 0.001 s = 2.38 kg-m/s