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Na+CL2=2NACL is the balanced reaction for the formation of table salt. Given 20 grams of Na and 10 grams of Cl2, which reactant is in excess? How much NaCL should be produced from these amounts of the two reactants?

Respuesta :

ardni313

Excess reactant : Na

NaCl produced : = 16.497 g

Further explanation

Given

Reaction(balanced)

2Na + Cl₂⇒ 2NaCl

20 g Na

10 g Clâ‚‚

Required

Excess reactant

NaCl produced

Solution

mol Na(Ar = 23 g/mol) :

= 20 : 23 = 0.87

mol Clâ‚‚(MW=71 g/mol):

= 10 : 71 g/mol = 0.141

mol : coefficient :

Na = 0.87 : 2 = 0.435

Clâ‚‚ = 0.141 : 1 = 0.141

Limiting reactant : Clâ‚‚(smaller ratio)

Excess reactant : Na

Mol NaCl based on mol Clâ‚‚, so mol NaCl :

= 2/1 x mol Clâ‚‚

= 2/1 x 0.141

= 0.282

Mass NaCl :

= 0.282 x 58.5 g/mol

= 16.497 g

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