expressed as a single logarithm. you do not need to expand the polynomials
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Answer:
Step-by-step explanation:
ln(x-2)^5
ln(x + 3)^8
ln(x + 3)^3
(x - 2)^5 * (x + 3)^8
================ Cancel the (x + 3)s
(x + 3)^3
(x- 2)^5 * (x + 3)^5
( (x - 2) *(x + 3) )^5
ln( (x - 2)(x + 3)^5 You could expand what's in the brackets.
ln( x^2 - 2x + 3x - 6)^5
ln(x^2 + x - 6)^5
the answer all depends on what you are given. If this answer proves to be wrong, write me a note under comments and I'll alter my answer.