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The length of a rectangle is twice its width. The perimeter is 60 ft. Find its area.
A = 200 ft ²
A = 10 ft ²
A = 100 ft ²​

The length of a rectangle is twice its width The perimeter is 60 ft Find its area A 200 ft A 10 ft A 100 ft class=

Respuesta :

Answer:

200ft^2

Step-by-step explanation:

From the first sentence;

L = 2B

Perimeter of a rectangle = 60ft

P = 2[ L +B ]

substitute as follows;

60 = 2( 2B + B)

60 = 2(3B)

60 = 6B

B = 10ft

To find L

L = 2B

L = 2*10

L = 20 ft

Area of a rectangle = LB

= 20×10

=200ft^2

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