Answer:
first
2x + 4 = 10
2x+4=10
2x+4=10
Solve
1
Subtract
4
4
4
from both sides of the equation
2
+
4
=
1
0
2x+4=10
2x+4=10
2
+
4
−
4
=
1
0
−
4
2x+4{\color{#c92786}{-4}}=10{\color{#c92786}{-4}}
2x+4−4=10−4
2
Simplify
Subtract the numbers
Subtract the numbers
2
=
6
2x=6
2x=6
3
Divide both sides of the equation by the same term
2
=
6
2x=6
2x=6
2
2
=
6
2
\frac{2x}{{\color{#c92786}{2}}}=\frac{6}{{\color{#c92786}{2}}}
22x=26
4
Simplify
Cancel terms that are in both the numerator and denominator
Divide the numbers
=
3
x=3
x=3
Solution
=
3
Second one
6 = 10
2
Simplify
Cancel terms that are in both the numerator and denominator
Divide the numbers
=
5
3
x=\frac{5}{3}
x=35
Solution = 5/3
i hope these help to figure out the third sorry its all messed up it wouldnt let me do another way
