Answer:
2.5secs
Step-by-step explanation:
Given the height of the ball modeled by the equation h = -16t^2+ 100, where
h is the height
t is in seconds
We can find the time taken by the ball to reach the ground.
The ball reaches the ground when the height h = 0
Substitute h = 0 into the equation and find t;
0 = -16t^2+ 100
16t^2 = 100
t^2 = 100/16
t = √100/16
t = 10/4
t = 2.5secs
Hence the ball reaches the ground after 2.5secs
