If Delta AGM sim Delta KXD , find the value of x.
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For ΔKXD, x = 21
"The triangles that have corresponding sides in proportion to each other and corresponding angles are equal."
For given question,
ΔAGM is similar to ΔKXD
This means,
[tex]\frac{AG}{KX} = \frac{GM}{XD} = \frac{AM}{KD}[/tex]
Consider,
⇒ [tex]\frac{AG}{KX} = \frac{GM}{XD}[/tex]
⇒ [tex]\frac{32}{x+3} = \frac{36}{x+6}[/tex]
⇒ [tex]32\times (x+6) = 36\times (x+3)[/tex]
⇒ [tex]32x+192=36x+108[/tex]
⇒ [tex]4x = 84[/tex]
⇒ x = 21
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