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Part A )a painter leans a ladder up against a building. The base of the ladder is placed 7 feet from the building to reach a height of 24 feet. How long is the ladder
Part B) The painter uses the same ladder from part A, but now needs to reach a height of 19 feet.How far away does the base of the ladder need to be placed from the building? ​

Part A a painter leans a ladder up against a building The base of the ladder is placed 7 feet from the building to reach a height of 24 feet How long is the lad class=

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Answer:

Part A). 25 feet

Part B). 16.25 feet

Step-by-step explanation:

Part A). By applying Pythagoras theorem in ΔABC,

            AC² = AB² + BC²

            AC² = (24)² + 7²

            AC² = 576 + 49

            AC = √625

                  = 25 feet

Part B). By applying Pythagoras theorem in ΔABC,

            AC² = AB² + BC²

           (25)² = (19)² + x²

           625 = 361 + x²

           x² = 625 - 361

           x = √264

           x = 16.25 feet

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