A racecar is traveling at a speed of 80.0 m/s on a circular
racetrack of radius 450 m. What is the centripetal force on the
racecar if its mass is 500 kg?

Respuesta :

A :-) F = mv^2 by r
Given - m = 500 kg
v = 80.0 m/s
r = 450 m
Solution -
F = mv^2 by r
F = 500 x (80)^2 by 450
F = 500 x 6400 by 450
( cut 500 and 450 because 5 x 100 = 5 , 5 x 90 = 450 and also 90 and 6400 because 90 x 70 = 6400 )
F = 100 x 70
F = 7000

.:. The centripetal force is 7000 N

The centripetal force on the  race car if its mass is 500 kg is 7,111.1N

The formula for calculating the centripetal force of the car is expressed as

[tex]C=\frac{mv^2}{r}[/tex]

m is the mass of the car

v is the velocity of the car

r is the radius of the circular path

Given the following parameters

m = 500kg

v = 80.0m/s

r = 450m

Substitute the given parameters into the formula as shown

[tex]F_c=\frac{500 \times 80^2}{450}\\F_c=\frac{500\times 6400}{450}\\ F_c=\frac{3,200,000}{450}\\F_c= 7,111.1N[/tex]

Hence the centripetal force on the  race car if its mass is 500 kg is 7,111.1N

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