Find the zero of the function.
g(x) = x2 + 22x + 121
The zero of the function is x=
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Answer:
x = -11
Step-by-step explanation:
To find the zero of this function, factor the equation:
g(x) = [tex]x^{2} +22x+121[/tex]
g(x) = (x + 11) (x + 11)
g(x) = [tex](x+11)^{2}[/tex]
The zeros of a function are the values of x that will make g(x) equal 0. So, the zero of this function is -11, because -11 + 11 = 0. So, x = -11.