alissajadeking
contestada

A piece of unknown metal with mass 68.6 g is heated to an initial temperature of 100 Ā°C and dropped into 42 g of water (with an initial temperature of 20 Ā°C) in a calorimeter. The final temperature of the system is 52.1Ā°C. The specific heat of water is 4.184 J/g*ā°C. What is the specific heat of the metal?
A.0.171
B.0.342
C.1.717
4.3.420

Respuesta :

taskmasters
The piece of unknown metal is in thermal equilibrium with water such that Q of metal is equal to Q of the water. We write this equality as follows:

-Qm = Qw
Mass of metalĀ (Cm)(Ī”T) = Mass of water (Cw)Ā (Ī”T)

where C is the specific heat capacities of the materials.

We calculate as follows:

-(Mass of metalĀ (Cm)(Ī”T)) = Mass of water (Cw)Ā (Ī”T)
-68.6Ā (Cm)(52.1 - 100) = 42 (4.184)Ā (52.1 - 20)
Cm = 1.717 -----> OPTION C
erodriguez55

Answer:

Option C

Step-by-step explanation:

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