Enter an equation in point-slope form for the line. (6,8) and (7,1) is on the line. The equation of the line in point slope form is:

Answer:
[tex] y - 8 = -7(x - 6) [/tex] or [tex] y - 1 = -7(x - 7) [/tex]
Step-by-step explanation:
The point-slope form equation is [tex] y - b = m(x - a) [/tex], where,
(a, b) = a point on the line.
[tex] m = slope = \frac{y_2 - y_1}{x_2 - x_1} [/tex]
Given the two points, (6, 8) and (7, 1), find the slope of the line:
[tex] m = \frac{1 - 8}{7 - 6} [/tex]
[tex] m = \frac{-7}{1} [/tex]
[tex] m = -7 [/tex]
There are two possible point-slope equation we can come up with using each points on the line given.
Using the point (6, 8) and m = -7,
Substitute m = -7, a = 6, and b = 8 into [tex] y - b = m(x - a) [/tex]
[tex] y - 8 = -7(x - 6) [/tex]
Using the point (7, 1) and m = -7,
Substitute m = -7, a = 7, and b = 1 into [tex] y - b = m(x - a) [/tex]
[tex] y - 1 = -7(x - 7) [/tex]