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ATTENTION
I have a decent bit of questions I need answered the person to answer these questions gets brainliest, a heart, and 5 stars go to my account for the questions

ATTENTION I have a decent bit of questions I need answered the person to answer these questions gets brainliest a heart and 5 stars go to my account for the que class=

Respuesta :

delancygenius

▪Answer: Option D!

Explanation:

Given:

  • y = x +7
  • [tex]y = {x}^{2} + 2x + 7[/tex]

Solution :

Substitute y=x + 7 in the second equation!

[tex]y = {x}^{2} + 2x + 7[/tex]

[tex] \implies \: x + 7 = {x}^{2} + 2x + 7[/tex]

[tex] \implies \: {x}^{2} + 2x + 7 - x - 7 = 0[/tex]

[tex] \implies \: {x}^{2} + x = 0[/tex]

[tex] \implies \: x(x + 1) = 0[/tex]

[tex] \implies \: x = 0 \: or \: x = - 1[/tex]

Now put x = 0 in equation 1,

y = x +7

=> y = 0+7

=> y = 7

Now put x=-1 in equation 1,

y = x+7

=> y = -1+7

=> y = 6

The solutions are :

  • (0,7) and
  • (-1, 6)

Option D!

3colorfulrainbows

Answer:

D

Step-by-step explanation:

plugin 0 for all x's to find the y-intercept

A doesn't work because if you plug in 1 for x in the first equation you get 10 and for the second equation you get 8. 10 and 8 are not equal

when you plug in -1 for x in both equation you get -6

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