2021ecarter
contestada

Solve 3x^2 + 17x - 6 = 0.
3x2 + 18x - x- 6 =0

3x(x+6) -1(x+6) =0

(3x-1)(x+6) =0

3x-1 or x+6 =0


Based on the work shown above, which of these values are possible solutions of the equation? Check all of the boxes that apply.


x=-6

x=6

x=-โ…“

x=โ…“

x=0

Respuesta :

zycholm23

Answer:

3x^2+17x-6=0.

a = 3; b = 17; c = -6;

ฮ” = b2-4ac

ฮ” = 172-4ยท3ยท(-6)

ฮ” = 361

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:

x1=โˆ’bโˆ’ฮ”โˆš2ax2=โˆ’b+ฮ”โˆš2a

ฮ”โˆ’โˆ’โˆš=361โˆ’โˆ’โˆ’โˆš=19

x1=โˆ’bโˆ’ฮ”โˆš2a=โˆ’(17)โˆ’192โˆ—3=โˆ’366=โˆ’6

x2=โˆ’b+ฮ”โˆš2a=โˆ’(17)+192โˆ—3=26=1/3

Step-by-step explanation:

maxisacow

Answer:

-6 and 1/3

Step-by-step explanation:

Otras preguntas