Answer:
3. B. P = 134x + 20y
4. J. (10, 150), I(40, 120), G(60, 100), C(60, 0) and E(10, 0)
5. C. 60 mopeds 100 bicycles
Step-by-step explanation:
3. The given information are;
The number of mopeds the company must produce per month = 10
The number of mopeds the company can produce month = 60
The number of bicycles the company can produce per month = 120
The total sum of the produced mopeds and bicycles ≤ 160
The profit on a moped = $134
The profit on a bicycle = $20
Given that the number of moped produced = x and the number of bicycles produced = y
Therefore, we have;
Profit, P = $134 × x + $20 × y
Which gives;
B. P = 134x + 20y
4) From Desmos, using the following constraints;
x + y ≤ 160
10 ≤ x ≤ 60
0 ≤ y ≤ 120 we have;
The vertices of the constraint for the feasible region are;
J. (10, 150), I(40, 120), G(60, 100), C(60, 0) and E(10, 0)
5) We note that since the profit from each moped is more than the profit from the sale of each bicycle, the maximum possible number of moped should be produced, while the rest should be used to produce bicycles
Therefore, given that from the vertices, the maximum possible number of moped = 60, the number of bicycles to be produced should be 160 - 60 = 100 bicycles
Which gives;
C. 60 mopeds 100 bicycles.
3. The objective function should be option B. P = 134x + 20y
4. The vertices of the feasible region, given the constraints should be J(10, 150), I(40, 120), G(60, 100), C(60, 0) and E(10, 0)
5. The number of each product that should be manufactured per month should be option C. 60 mopeds 100 bicycles
3.
Here we assume that the number of mopeds produced = x
and the number of bicycles produced = y
So, the profit equation should be
Profit, P = $134 × x + $20 × y
That provides P = 134x + 20y
4) From Desmos, we used the following constraints;
x + y ≤ 160
10 ≤ x ≤ 60
0 ≤ y ≤ 120 we have;
So, The vertices of the constraint should be
J. (10, 150), I(40, 120), G(60, 100), C(60, 0) and E(10, 0)
5) The maximum no of mopeds should be 60
And, the no of bicycles that need to be produced is
= 160 - 60
= 100 bicycles
That provides  60 mopeds 100 bicycles.
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