During high around 11:00p.m the water level is 3 feet above a marker on a pier. The following day, around 5:12 a.m., the water level has dropped 3 feet below the marker. The height of the water is modeled by the function y=3 cos ( 24pi/149 x). where x is the time in since 11:00p.m. What is the height of the water at 2:15 a.m.? 0.22 feet below the marker 0.07 feet below the marker 1.26 feet above the marker 1.39 feet above the marker

Respuesta :

Answer: 0.22 feet below the market

Step-by-step explanation:

If you plug in 3.25 (hours after 11pm) into the equation for x, you would get -0.22

Answer: a) 0.22 ft below the marker