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This video demonstrates the Monty Hall Problem, named after the host of the game show "Let's Make a Deal" that originally aired in the 1960s and 1970s. In this show, contestants picked one of three curtains, one of which had a car behind it and the other two had goats. After contestants chose a curtain, Monty Hall showed the contestant what was behind one of the two curtains the contestant had not chosen. Then he offered the contestant the option to switch her choice.

A. 3

B. 10

C. 20

D. 40

Respuesta :

Answer:

The answer is "Option C".

Step-by-step explanation:

There are goats behind two curtains, one behind every door.  

Whenever a contender chooses a curtain, this contender is told the curtain had a goat behind all this by one of the certain to curtains.  

Currently, one of two curtains another containing the car and one bearing a goat is provided to be chosen by the contestant. There is therefore an equal probability of [tex]\frac{1}{2}[/tex].  Picking a car or a goat.  

Similarly, provided that

Strategies and tactics likelihood A= 10 % = 2 in 20 trails effective.  

Stratery B's chance = 80 % = 16 achievements in 20 directions = 80%  

Therefore,

[tex]\to \text{16 success} = 2 \ success+2\ success + 2\ success + 2\ success+ 2\ success +2\ success + 2\ success+ 2\ success + 2\ success}\\\\\to 16 \ success = 8(2 \ success) \\[/tex]

[tex]\to 80 \% = 8 \times 10 \% \\\\\to 80 \% = 80 \%[/tex]

its result value is expected not surprising.

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