Using the following image, if DF= 120, what are x, DE, and EF.

From the given information x = 19, and the segments DE = 84 and EF = 36.
The length of the line segment formed by the joining of two or more line segments is the summation of the lengths of all the smaller segments.
In the question, we are shown a line segment DF = 120, made of two smaller segments DE = 4x + 8 and EF = 2x - 2.
As DF is made of DE and EF,
The length of DF = The length of DE + The length of EF
or, 120 = 4x + 8 + 2x - 2
or, 120 = 6x + 6
or, 6x = 120 - 6 = 114
or, x = 114/6 = 19.
Therefore, DE = 4x + 8 = 4(19) + 8 = 76 + 8 = 84
EF = 2x - 2 = 2(19) - 2 = 38 - 2 = 36
Therefore, from the given information x = 19, and the segments DE = 84 and EF = 36.
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