Point I is on line segment HJ. Given I J equals 3X +3, HI equals 3X-1, and HJ equals 3X +8, determine the numerical length of HJ.
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Answer:14
Step-by-step explanation:
3x + 3 + 3x - 1 = 3x + 8
6x + 2 = 3x + 8
3x + 2 = 8
3x = 6
x = 2
HJ= 3(2) + 8 =6 + 8 = 14
HI= 3(2) - 1 = 6 - 1 = 5
IJ = 3(2) + 3 = 6 + 3 = 9
The numerical value of the length HJ such that will be I J equals 3X +3, HI equals 3X-1, and HJ equals 3X +8 will be 14.
A line section that can connect two places is referred to as a segment.
In other words, a line segment is just part of a big line that is straight and going unlimited in both directions.
The line is here! It extends endlessly in both directions and has no beginning or conclusion.
Given that the line HJ has a length of 3x+8
HJ = 3x+8
The line segment HI has a length of 3x -1
HI = 3x -1
The line segment IJ is 3x + 3
IJ = 3x + 3
Since line HJ = HI + IJ
3x -1 + 3x + 3 = 3x+8
x= 2
The length of HJ will be
HJ = 3(2) + 8
HJ = 14 hence, 14 will be the correct answer.
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