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WILL GIVE BRAINLIEST!!!!!! Look at the picture of a scaffold used to support construction workers. The height of the scaffold can be changed by adjusting two slanting rods, one of which, labeled PR, is shown: Part A: What is the approximate length of rod PR? Round your answer to the nearest hundredth. Explain how you found your answer, stating the theorem you used. Show all your work. Part B: The length of rod PR is adjusted to 17 feet. If width PQ remains the same, what is the approximate new height QR of the scaffold? Round your answer to the nearest hundredth. Show all your work.

WILL GIVE BRAINLIEST Look at the picture of a scaffold used to support construction workers The height of the scaffold can be changed by adjusting two slanting class=

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ChocoChocoCho

A) Here, We'll use "Pythagoras Theorem" which tells:

a² + b² = c²

So, PR² = PQ² + QR²

PR² = 14² + 9²

PR² = 196 + 81

PR = √277

In short, Your Answer would be 16.64 Feet

B) Again, Use the Pythagoras Theorem,  

c² - a² = b²

18² - 14² = b²

b² = 324 - 196

b = √128

b = 11.31

In short, Your Answer would be 11.31 Feet

OceanSong

Part A: Using the Pythagorean Theorem. a^2 + b^2 = c^2

PQ^2 + QR^2 = PR^2  (The rods make a right triangle, where PR would be the hypotenuse, and QR and PQ would be legs a and b.)

14^2 + 9^2 = PR^2

196 + 81 = PR^2

Square root of 277 = PR 

16.64 = PR

So, the hypotenuse would be equal to 16.64 ft.

Part B: Using the Pythagorean Theorem. a^2 + b^2 = c^2

PR^2 - PQ^2 = QR^2 (Trying to find the height of QR this time, not the hypotenuse, since we know what it is already. Subtracting the value of leg a from the hypotenuse will give us the value of leg b, QR.)

18^2 - 14^2 = QR^2

324 - 196 = QR^2

Square root of 128 = QR

So, the new height of QR would be 11.31 ft.

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