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100 POINTS!The number of pizzas sold in one weekend at Pete's Pizzas is shown. Pie chart of pizza sales. Data includes: 130 hamburger, 175 pepperoni, 60 cheese, and 35 veggie. a) If Pete's sales remain consistent, how many pepperoni pizzas will he have sold when the total number of pizzas sold reaches 1600? b) How would the circle graph be different if Pete had sold 200 pepperoni pizzas, 100 hamburger pizzas, 50 veggie pizzas, and 50 cheese pizzas?

100 POINTSThe number of pizzas sold in one weekend at Petes Pizzas is shown Pie chart of pizza sales Data includes 130 hamburger 175 pepperoni 60 cheese and 35 class=

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ujalakhan18

Answer:

A) [tex]\boxed{\sf 700 \ pepperoni \ pizzas}[/tex]

B) See the attached file!

Step-by-step explanation:

Total pizza sales in the pie chart = 175+60+35+130

=> 400 total Pizzas

Out of these 400, there are 175 pepperoni pizzas

So,

Pepperoni Pizzas = 175/400 = 7/16 (Simplest form)

So,

Among 1600 pizzas, pepperoni pizzas would be:

=> [tex]\frac{7}{16} * 1600[/tex]

=> 7 * 100

=> 700 pepperoni pizzas

Part B)

See the attached file:

Ver imagen ujalakhan18
09pqr4sT

Answer:

[tex]\sf a) \ 700 \\ b) \ \sf view \: attachment[/tex]

Step-by-step explanation:

Part A:

Calculate the total parts:

[tex]130+175+60+35[/tex]

[tex]=400[/tex]

Out of 400 pizzas, 175 are pepperoni.

[tex]\frac{175}{400}[/tex]

The sales remain constant, if the total number of sold pizzas reaches 1600 then:

[tex]\frac{175}{400} \times 1600[/tex]

[tex]=700[/tex]

Out of the 1600 pizzas sold, 700 would be pepperoni.

Part B:

(attachment)

Pepperoni pizza:

[tex]\frac{200}{200+100+50+50} =\frac{1}{2}[/tex]

Hamburger pizzas:

[tex]\frac{100}{200+100+50+50} =\frac{1}{4}[/tex]

Veggie and cheese pizzas:

[tex]\frac{50}{200+100+50+50} =\frac{1}{8}[/tex]

Ver imagen 09pqr4sT

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