Respuesta :

Answer:

The length of segment A'E' is 5 units

Explanation:

From the included graph the coordinates of the points A and E, in the pentagon ABCDE with reference to point A are;

A- (0, 0)

E- (0, 2)

The length of the segment AE = √((2-0)² + (0 - 0)²) = √2² = 2

When a pentagon ABCDE is dilated to pentagon A'B'C'D'E' with a scale factor of 5/2, we have;

Length of segment A'E' = 5/2 × Length of segment AE

Therefore;

Length of segment A'E' = 5/2 ×2 = 5 units.

The length of segment A'E' is 5 units.

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shristiparmar1221

This question is based on distance formula.The length of segment A'E' is 5 units.

Given:

Pentagon A’B′C′D′E’, is the image of pentagon ABCDE under a dilation with a scale factor of 5/2.

From the given  graph, the coordinates of the points A and E, in the pentagon ABCDE with reference to point A are;

A- (0, 0)

E- (0, 2)

The length of the segment AE = [tex]\sqrt{(2-0)^{2} +(0-0)^{2} }=\sqrt{2^{2} } =2[/tex]

When a pentagon ABCDE is dilated to pentagon A'B'C'D'E' with a scale factor of 5/2, we have;

Length of segment A'E' = 5/2 × Length of segment AE

Therefore;

Length of segment A'E' = 5/2 ×2 = 5 units.

Therefore, the  length of segment A'E' is 5 units.

For more details, please refer to this link:

https://brainly.com/question/23700761

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