Answer:
[tex]$\frac{-x^2+12x-12}{4x(x+4)(x-1)}$[/tex]
Step-by-step explanation:
[tex]$\frac{6}{2x(x+4)}- \frac{x}{4(x+4)(x-1)} $[/tex]
[tex]$\frac{6\cdot2(x-1)}{2x(x+4)\cdot2(x-1)}- \frac{x\cdot x}{4(x+4)(x-1)x} $[/tex]
[tex]$\frac{12(x-1)}{4x(x+4)(x-1)}- \frac{x^2}{4x(x+4)(x-1)} $[/tex]
[tex]$\frac{12(x-1)-x^2}{4x(x+4)(x-1)}$[/tex]
[tex]$\frac{-x^2+12x-12}{4x(x+4)(x-1)}$[/tex]
