Because cylinder with a volume of 3.00dm^3 contains 8.00 moles of oxygen gas at a temperature of 50.0 K. What is the pressure inside the cylinder? ( R=8.31)
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Answer:
Option A. 1110 KPa.
Explanation:
The following data were obtained from the question:
Volume (V) = 3 dm³
Number of mole (n) = 8 moles
Temperature (T) = 50K
Gas constant (R) = 8.31 KPa.dm³/Kmol
Pressure (P) =..?
Pressure inside the cylinder can be obtained by using the ideal gas equation as follow:
PV =nRT
P x 3 = 8 x 8.31 x 50
Divide both side by 3
P= (8 x 8.31 x 50) /3
P = 1108 ≈ 1110 KPa
Therefore, the pressure inside the cylinder is 1110 KPa