Answer:
D. 6
6y^2 + 12y + 2 (simplified)
Step-by-step explanation:
- The equation of the parabola with vertex (h,k) is x = a(−k+y)^2+h.
- Thus, the equation of the parabola is x = a(y+1)^2−4.
- To find a, use the fact that the parabola passes through the point (2,0): 2 = a−4.
- Solving this equation, we get that a = 6.
- Thus, the equation of the parabola is x = 6(y+1)^2−4.
OR
- 6y^2 + 12y + 2 (simplified)
**If the parabola is rotated so that its vertex is (h,k) and its axis of symmetry is parallel to the x-axis, it has an equation of (y - k)2 = 4p (x - h), where the focus is (h + p, k) and the directrix is x = h - p.
