Respuesta :

dalendrk
[tex]11-\dfrac{1}{2}y=3+6x\ \ \ \ \ |subtract\ 11\ from\ both\ sides\\\\-\dfrac{1}{2}y=-8+6x\ \ \ \ \ |change\ signs\\\\\dfrac{1}{2}y=8-6x\ \ \ \ \ |multiply\ both\ sides\ by\ 2\\\\y=4-3x[/tex]

Answer:

The value of the provided equation for y is [tex]y=-12x+16[/tex].

Step-by-step explanation:

Consider the provided equation.

[tex]11-\frac{1}{2}y=3+6x[/tex]

We need to solve the above equation for y.

Subtract 11 from both the sides.

[tex]11-11-\frac{1}{2}y=3-11+6x[/tex]

[tex]-\frac{1}{2}y=6x-8[/tex]

Multiply both the sides by -2

[tex]-\frac{1}{2}y\times -2=-2(6x-8)[/tex]

[tex]y=-12x+16[/tex]

Hence, the value of the provided equation for y is [tex]y=-12x+16[/tex].

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