Answer:
Option A. ⅓V
Explanation:
We'll begin by calculating the total resistance in the circuit. This is illustrated below:
R1 = 1Ω
R2 = 2Ω
R3 = 3Ω
RT =..?
Since all three resistor are in series connections, the total resistance can obtain as follow:
RT = R1 + R2 + R3
RT = 1 + 2 + 3
RT = 6Ω
Next we shall determine the current flowing through the circuit.
Voltage (V) = 2V
Resistor (R) = 6Ω
Current (I) =..?
V = IR
2 = I x 6
Divide both side by 6
I = 2/6
I = ⅓A
Finally, we can obtain the voltage across the 1Ω resistor as follow:
Resistor (R) = 1Ω
Current (I) = ⅓A
Voltage (V) =?
V = IR
V = ⅓ × 1
V = ⅓V
Therefore, the potential difference across the 1Ω resistor is ⅓V
