Find the 8th term in the sequence
-1/2, -1, -2, -4......
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Answer:
-64
Step-by-step explanation:
geometric
equation
a1(r)^n-1
-1/2(2)^8
Given sequence is -1/2, -1, -2, -4,...
We get,
a1 = -1/2
r = 2
n = 8
So,
a8 = a.r^(n-1)
a8 = -1/2 * 2^(8-1)
a8 = -1/2 * 2^7
a8 = -1/2 * 128
a8 = -64
Therefore, 8th term of the sequence is -64
A common ratio multiplied to each term to get the next term is a non-zero number is a geometric sequence. An example of a Geometric sequence is 2, 4, 8, 16, 32, 64, … , where the common ratio is 2.
- Arithmetic sequences
- Geometric sequences
- Quadratic sequences
- Special sequences
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