The solubility of a gas in water is 0.66 g/L at 15 kPa of pressure. What is the solubility when the pressure is increased to 40.0 kPa?

Respuesta :

Answer:

The correct answer to the following question will be "1.76 g/L".

Explanation:

The given values are:

P₁ = 15 kPa

Solubility of water, C₁ = 0.66 g/L

P₂ = 40.0 kPa

C₂ = ?

Now,

According to Henry's Law,

⇒  [tex]\frac{P_{1}}{P_{2}}=\frac{C_{1}}{C_{2}}[/tex]

⇒  [tex]C_{2}=\frac{C_{1}\times P_{2}}{P_{1}}[/tex]

On putting the estimated values, we get

⇒       [tex]=\frac{0.66\times 40}{15}[/tex]

⇒       [tex]=\frac{26.4}{15}[/tex]

⇒       [tex]=1.76 \ g/L[/tex]