find the value of sec (θ)for an angle θ in standard position with a terminal Ray that passes through the point (4, -3)
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Answer:
B
Step-by-step explanation:
See the attachment.
We know that since the point is (4, -3), it's in the fourth quadrant. Drop a perpendicular from the point to the x-axis and produce a right triangle. This triangle has opposite as length -3 and adjacent as 4. We need to find the hypotenuse, so use the Pythagorean Theorem:
c² = a² + b²
c² = (-3)² + 4² = 9 + 16 = 25
c = 5
Secant is hypotenuse over adjacent, so we have:
sec(θ) = 5/4
The answer is B.
Answer:
b
Step-by-step explanation:
Please see attached picture for full solution.