does anyone know how to do this?? steps are helpful but not necessary
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Answer:
C. [tex]\frac{2(x+16)}{x+4}[/tex]
Step-by-step explanation:
We want fg of x, so first we have to multiply f(x) times g(x).
[tex]\frac{x+16}{x} * \frac{2x}{x+4}[/tex]
[tex]\frac{(x+16)2x}{x(x+4)}[/tex]
[tex]\frac{2x^{2}+32x}{x^{2}+4x}[/tex]
We can cancel out an x from every term.
[tex]\frac{2x+32}{x+4}[/tex]
Let's rewind a little to get this into one of the answer choices.
[tex]\frac{2(x+16)}{x+4}[/tex] is our answer.