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2) If you wanted to solve for mZQ, which of the following equations is
correct? *
1 poin
sin Q = 4/3
cos Q = 4/3
O
tan Q = 4/3
3) If siny - 5/12
il

2 If you wanted to solve for mZQ which of the following equations is correct 1 poin sin Q 43 cos Q 43 O tan Q 43 3 If siny 512 il class=

Respuesta :

Answer:

tanQ = [tex]\frac{4}{3}[/tex]

Step-by-step explanation:

Since the hypotenuse is not known this rules out sine and cosine ratios.

tanQ = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{4}{3}[/tex]

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